Question

Pls ans briefly explain

Answer 1

The force of gravitational will decreases by a factor of 4

Step-by-step explanation:

The given parameters are;

The symbol that represents the given mass = m

The mass of the circular ring = M

The initial distance of the mass "m" located at the point P from the center O = h

The final distance of the mass "m" when moved further away from point O = 2·h

Given that h = r, we have;

`The \ initial \ gravitational \ force, F_1 =G \cdot (M \cdot m)/(r^(2))`

Therefore, when OP = 2·h, we have;

OP = 2·r and the new gravitational force, F₂, is given as follows;

`F_2 =G \cdot (M \cdot m)/((2\cdot r)^(2)) = G \cdot (M \cdot m)/(4\cdot r^(2)) = (1)/(4) * G \cdot (M \cdot m)/(r^2) = (1)/(4) * F_1`

`\therefore F_2 = (1)/(4) * F_1`

Therefore, when the mass, m, is removed such that OP = 2h, the value of the gravitational force decreases by a factor of 4.