Question

Tha area of a triangle is 5x^3+19x2+6x-18 with length x+3. Using synthetic division,what is the width of the rectangle

A)5x^2+4x-6

B)5x^2+34x+108+306/x+3

C)5x^3+4x^2-6x

D)5x^2+34+108+306/x-3

Answer 1

we know that

area of rectangle = length*width

Let's assume

length of rectangle is L

width of rectangle is W

`A=L*W`

we are given

`A=5x^3+19x^2+6x-18`

`L=x+3`

now, we can find width

`W=(A)/(L)`

now, we can plug values

`W=(5x^3+19x^2+6x-18)/(x+3)`

we can use synthetic divison method

we get

`W=(5x^3+19x^2+6x-18)/(x+3)=5x^2+4x-6`

`W=5x^2+4x-6`

so, option-A...........Answer