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A web page designer creates an animation in which a dot on a computer screen has a position of r⃗ =[ 4.2 cm +( 2.5 cm/s2 )t2]i^+( 5.5 cm/s )tj^ .find the average velocity of the dot between t=0 and t=2.0s. give your answer as a pair of components separated by a comma. for example, if you think the x component is 3 and the y component is 4, then you should enter 3,4. express your answer using two significant figures.

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we are given


r(t)=(4.2cm+(2.5cm/s^2)t^2)i+(5.5cm/s)tj

Firstly, we will plug t=0 and t=2

Calculation of r(0):


r(0)=(4.2cm+(2.5cm/s^2)*0^2)i+(5.5cm/s)*0j


r(0)=4.2i+0j

Calculation of r(2):


r(2)=(4.2cm+(2.5cm/s^2)*2^2)i+(5.5cm/s)*2j


r(2)=(4.2+5)i+(11)j


r(2)=(9.2)i+(11)j

Average velocity:

now, we can use formula


v=(r(2)-r(0))/(2-0)

now, we can plug values


v=(((9.2)i+(11)j)-(4.2i+0j))/(2-0)


v=(5i+11j)/(2-0)


v=(2.5cm/s) i+(5.5cm/s)j..............Answer


User Ferran Buireu
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