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Given that you added 5 ug of a purified acid phosphatase to tube a, calculate the amount of acid phosphatase (in ug) that was present in the 400ul of the wheat germ extract in tube b

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solution:


Amount of purified acid phosphatase added to tube A = 5\mu g(micrograms)\\</p><p>Amount of acid phosphatase present in 400\mu g of wheat germ extract in tube B=1/100=5x/400\\</p><p>100x=(0.5)(400)\\</p><p>X=(0.5)(400)/100=2\mu g\\</p><p>The amount of acid phosphatase present in 400\mu g of the wheat germ extract in tube B is 2\mu g

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