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−5x + 1 ≥ x − 5 4x − 5(x + 1) ≤ 2 −3(x − 1) > 4 6(x + 3) − 2 ≤ 4x 5(x + 1) ≥ 3x + 4 can you guys help me with this for free cookiesXDXD

−5x + 1 ≥ x − 5 4x − 5(x + 1) ≤ 2 −3(x − 1) > 4 6(x + 3) − 2 ≤ 4x 5(x + 1) ≥ 3x + 4 can you guys help me with this for free cookiesXDXD
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1 vote
−5x + 1 ≥ x − 5

4x − 5(x + 1) ≤ 2
−3(x − 1) > 4
6(x + 3) − 2 ≤ 4x
5(x + 1) ≥ 3x + 4
can you guys help me with this for free cookiesXDXD

User Dutch
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Download Photomath trust me it will help you
User Yehoshua
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