Given:
An exponential function
passes through the points (0, 12000) and (2, 3000).
To find:
The values of a and b.
Solution:
We have,
...(i)
It passes through the point (0,12000). Putting x=0 and f(x)=12000 in (i), we get



Given function passes through the point (2,3000). Putting x=2, a=12000 and f(x)=3000 in (i), we get



Taking square root on both sides.

For an exponential function b cannot be negative. So,
.
Therefore, the value of a is 12000 and the value of b is
.