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Player B’s longest home run distance is 500 ft. There are 5280 ft in 1 mi. How many home runs would Player B need to hit at his longest distance for the total to be greater?

Player B’s longest home run distance is 500 ft. There are 5280 ft in 1 mi. How many home runs would Player B need to hit at his longest distance for the total to be greater?
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Player B’s longest home run distance is 500 ft. There are 5280 ft in 1 mi. How many home runs would Player B need to hit at his longest distance for the total to be greater?

User Doptrois
by
9.1k points

1 Answer

4 votes
5280 ÷ 500 = (number of home runs needed to reach a mile distance)

5280 ÷ 500 = 10.56

cant hit part of a home run so round up to 11.
User GNerb
by
8.5k points
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