Question

Can some one please help me with this problem

Answer 1

• The area of EFGH is 234 m².

Explanation:

We know that:

• 4(AB + BC + CD + DA) = EF + FG + GH + HE
• EF = 9m
• AB = CD = 2.25 m
• DA = BC = 6.5 m
• Area of EFGH = EF x FG

Work:

• 4(AB + BC + CD + DA) = EF + FG + GH + HE
• => 4(2.25) + 4(6.5) + 4(2.25) + 4(6.5) = 9 + FG + GH + HE
• => 9 + 26 + 9 + 26 = 9 + FG + GH + HE
• => 26 + 9 + 26 = FG + GH + HE
• => FG = 26; GH = 9; HE = 26
• => Area of EFGH = EF x FG
• => Area of EFGH = 9 x 26
• => Area of EFGH = 234 m²

Hence, the area of EFGH is 234 m².

Hoped this helped.

`BrainiacUser1357`

Answer 2

234.0 sq. meters

Explanation:

Since the rectangles are similar, it means that there is a common ratio between the width and length.

Since the length of ABCD is given at 2.25m and length of EFGH is given at 9, let's find a common ratio to find how much this big rectangle is multiplied by from Rectangle ABCD.

9/2.25=4

This 4 means that ABCD is being multiplied in size by 4 to equal EFGH.

Let's multiply 6.5m by 4 to get the width for EFGH.

6.5*4=26m

Now that we have the width and length, we can find the area which is length times height:

26m*9m=234.0 sq. meters