Question

Find the distance CD rounded to the nearest tenth.

Answer 1

The distance between points A and B is :

`d(A,B)=4√(17) = 16.4924...`

Step-by-step explanation

To find distance between points A(xA,yA) and B(xB,yB), we use formula:

`d(A, B) = \sqrt{(xB-xA)^(2)+(yB-yA)^(2)}`

In this example: xA=10 , yA=−1 , xB=−6 and yB=3 so:

`d(A, B) = \sqrt{(-6-10)^(2)+(3--1)^(2)}\\d(A, B) = \sqrt{(-16)^(2)+(4)^(2)}\\d(A, B) = √((256+16)\\d(A, B) = √(272)\\ d(A, B) = 16.4924...`

Therefore, rounded to the nearest tenth, the answer is 16.5.