Question

Hey how would you put this in a system equation and using the Elimination method. Thank you❤

Answer 1

The answer to the question

Answer 2

`\bf \begin{cases} t=tacos\\ m=milk \end{cases}~\hspace{7em} \begin{cases} \stackrel{1~taco}{t}+\stackrel{1~glass}{m}=\stackrel{\$}{2.10}\\[0.8em] \stackrel{2~tacos}{2t}+\stackrel{3~glasses}{3m}=\stackrel{\$}{5.15} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{array}{llll} t+m=2.10&\stackrel{multiplied~by}{* -3}\implies &\stackrel{notice}{-3t\stackrel{\downarrow }{-3m}=-6.3}\\[0.8em] 2t+3m=5.15&\implies &~~2t+3m=5.15\\ \cline{3-3} &&-t+0m=-1.15 \end{array} \\\\[-0.35em] ~\dotfill`

`\bf -t=-1.15\implies t=\cfrac{-1.15}{-1}\implies \blacktriangleright t=1.15 \blacktriangleleft \\\\\\ \stackrel{\textit{and now substituting on the 2nd equation}}{2(1.15)+3m=5.15}\implies 2.3+3m=5.15 \\\\\\ 3m=2.85\implies m=\cfrac{2.85}{3}\implies \blacktriangleright m=0.95 \blacktriangleleft`

notice, we used -3 in the multiplication to eliminate the m's.