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What value of satisfies the equation 2n-3(4n+5)=-6(n-3)-1
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What value of satisfies the equation 2n-3(4n+5)=-6(n-3)-1

User Querenker
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1 Answer

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2n-12n -15 = -6n +18 -1

-10n -15 = -6n +17

+6n +6n

-4n -15 = 17

+15 +15

-4n = 32

Divide both sides by -4

N= -8
User Alexander Revutsky
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