Question

A yogurt shop allows its customers to add, for no charge, 3 toppings to any yogurt purchased. If the store has 15 possible toppings, how many different 3-topping combinations can a customers choose?

Answer 1

hello so i took this test and got the answer correct soooooo the answer is basically 8, have a good day chow

Explanation:

Answer 2

The number of different 3-topping combinations a customers can choose is:

455

Explanation:

We know that the number of ways to choose r items out of a given n items is calculated with the help of method of COMBINATION.

The formula is given by:

`n_C_r=(n!)/(r!* (n-r)!)`

We have n=15 and r=3

Hence, the number of combinations possible is given by:

`{15}_C_3=(15!)/(3!* (15-3)!)\\\\\\{15}_C_3=(15!)/(3!* 12!)\\\\\\{15}_C_3=(15* 14* 13* 12!)/(3!* 12!)\\\\\\{15}_C_3=(15* 14* 13)/(3* 2)\\\\\\{15}_C_3=455`

The answer is:

455