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Given:
B(Magnetic field): 1.5 T
q= 7.5 microcoulombs
v= 1.75 x 10 ∧6 m/s
The angle ∅ between B and v is 45 °.
Now we know that F= qvB sin ∅
Substituting these values we get:
F= 7.5 x 10∧-6 x 1.75 x 10∧6 x 1.5 x sin 45
F= 16.752 N
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