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A 201  g lead ball at a temperature of 

88.1 °C is placed in a light calorimeter containing 178 g of water at 24.5°C. Find the equilibrium temperature of the system.
User Hover Ruan
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1 Answer

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it would be 0.201*(273+88.1) + 0.178*(273+24.5) / (0.178+0.201) which comes to 331 Kelvin approximately 58° C
User Nicolas Cortot
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