153k views
5 votes
The graph of y=6-[sqrt(4-3x)] contains which point?

A. (1,4)
B.(0,1)
C.(0,6)
D. (1,5)
E. (2,4)
F. None of the above

1 Answer

4 votes

Given y=6-[sqrt(4-3x)], focus on the sqrt function: sqrt(4-3x). Since the input of this function cannot be negative, any x-value used must pass the test 4-3x>0. This is equivalent to 4>3x, or 3x<4, or x < 4/3. This eliminates choice E.

Second, if the y value is an integer, then sqrt(4-3x) must be an integer.

Checking answers A through D:

A: sqrt(4-3) = sqrt(1) = 1 (OK) Then y=6-[sqrt(1)] = 5 (NO)

B: sqrt(4-0) = 2 (OK) Then y=6-2 = 4 (NO)

C: sqrt(4-0) = 2 (OK) Then y=6-2 = 4 (NO)

D: sqrt(4-15) Not OK; eliminate

Correct answer: F: None of the above answers are correct

User Mantorok
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories