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The graph of y=6-[sqrt(4-3x)] contains which point?

A. (1,4)
B.(0,1)
C.(0,6)
D. (1,5)
E. (2,4)
F. None of the above

1 Answer

4 votes

Given y=6-[sqrt(4-3x)], focus on the sqrt function: sqrt(4-3x). Since the input of this function cannot be negative, any x-value used must pass the test 4-3x>0. This is equivalent to 4>3x, or 3x<4, or x < 4/3. This eliminates choice E.

Second, if the y value is an integer, then sqrt(4-3x) must be an integer.

Checking answers A through D:

A: sqrt(4-3) = sqrt(1) = 1 (OK) Then y=6-[sqrt(1)] = 5 (NO)

B: sqrt(4-0) = 2 (OK) Then y=6-2 = 4 (NO)

C: sqrt(4-0) = 2 (OK) Then y=6-2 = 4 (NO)

D: sqrt(4-15) Not OK; eliminate

Correct answer: F: None of the above answers are correct

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