The total ball pressure is sum of gauge pressure and atmospheric pressure
We know that atmospheric pressure = 101.325 kPa
so the total ball pressure = 61 kPa + 101.325 kPa = 162.325 kPa
Now we will use ideal gas equation as
PV = nRT
P = pressure = 162.325 kPa
V = 5.2 L
R = gas constant = 8.314 kPa L / mol K
T = 32 C = 273.15 + 32 = 305.15 K
n = moles = ?
Moles = PV / RT = 162.325 kPa X 5.2 / 305.15 X 8.314 = 0.332 moles