Question

A cross-country skier is skiing along at a zippy 8.0 m/s. She stops pushing and simply glides along, slowing to a reduced speed of 6.0 m/s after gliding for 5.0 m. What is the magnitude of her acceleration as she slows

Answer 1

The magnitude of her acceleration is -2.8 m/s²

Step-by-step explanation:

It is given that,

Initial velocity of the skier, u = 8 m/s

Final velocity of the skier, v = 6 m/s

Distance covered, s = 5 m

We need to find the magnitude of acceleration as she slows down. It can be calculated using third equation of motion as :

`v^2-u^2=2as`

`a=(v^2-u^2)/(2s)`

`a=((6\ m/s)^2-(8\ m/s)^2)/(2* 5\ m)`

`a=-2.8\ m/s^2`

Answer:

The magnitude of her acceleration is -2.8 m/s²

Step-by-step explanation:

It is given that,

Initial velocity of the skier, u = 8 m/s

Final velocity of the skier, v = 6 m/s

Distance covered, s = 5 m

We need to find the magnitude of acceleration as she slows down. It can be calculated using third equation of motion as :

`v^2-u^2=2as`

`a=(v^2-u^2)/(2s)`

`a=((6\ m/s)^2-(8\ m/s)^2)/(2* 5\ m)`

`a=-2.8\ m/s^2`

So, the acceleration of the skier is -2.8 m/s². Hence, this is the required solution.