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What is the half-life (in seconds) of a zero-order reaction which has an initial reactant concentration of 0.834 m with a k value of 5.42 × 10–2 m/s?

User SnowBlind
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Final answer:

The half-life of a zero-order reaction depends on the rate constant and initial concentration. For a reaction with an initial concentration of 0.834 M and a rate constant of 5.42 × 10⁻² M/s, the half-life is calculated as 7.69 seconds.

Step-by-step explanation:

The half-life of a zero-order reaction is the time required for the reactant concentration to decrease to one-half its initial value. In a zero-order reaction, this half-life depends on both the rate constant and the initial concentration of the reactant. The equation for the half-life of a zero-order reaction can be derived from the integrated zero-order rate law, which is [A] = -kt + [A]o. By setting [A] to one-half of [A]o, we can solve for the half-life.In this case, the initial concentration ([A]o) is 0.834 M and the rate constant (k) is 5.42 × 10⁻² M/s. The equation for the half-life (t1/2) of a zero-order reaction is given by t1/2 = [A]o / (2k). Plugging in the values, we get: t1/2 = 0.834 M / (2 × 5.42 × 10⁻² M/s)

After simplifying, the half-life of the reaction can be found. Thus, for a zero-order reaction with these specified conditions, the half-life is calculated to be 7.69 seconds.

User Anupal
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The half life (in seconds) of a zero order reaction which has an initial reactant concentration of 0.834 m and k value of 5.42 x10^-2 m/s is 7.694 sec

calculation

t 1/2= [Ao]/ 2k

wher Ao = initial concentration and k = constant

t 1/2= 0.834 m/ (2x5.42 x10^-2 m/s)=7.694 sec

User Abskmj
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