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A boy pulls a wagon with a force of 20 N on a handle .50 meters long. The end is .25 meters higher the the end attached to the wagon. What is the magnitude of the horizontal component that acts to pull
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22 votes
22 votes
A boy pulls a wagon with a force of 20 N on a handle .50 meters long. The end is .25 meters higher the the end attached to the wagon. What is the magnitude of the horizontal component that acts to pull the wagon forward?

User Adit Gupta
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1 Answer

17 votes
17 votes
Divide .25m/.50m for a total of .50
This is sort of like cosθ=adj/hyp=.25/.50=.600

Cos^-1 for .50 and your angle is 60°.

After that do 20N·sin 60°
This is hyp· sin θ

Your answer being 17N
User Anirban
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