Question

Use hookes law

A force of 265 newtons stretches a spring 0.15 meters a) what force stretches the spring 0.2
B)how far does a force of 140 Newton’s stretch the spring

Answer 1

we know that

Hooke's law

`F=kx`

where

F is force

k is spring constant

x is stretched length

we are given F=265N and x=0.15m

now, we can use it and find k

`265=k*0.15`

we get

`k=(5300)/(3)`

now, we can plug back

`F=(5300)/(3)x`

(A)

we are given

stretches the spring 0.2

so, x=0.2

and then we can find F

`F=(5300)/(3)*0.2`

`F=353.333N`

(B)

we are given

F=140N

so, we can set it equal and then we can solve for x

`140=(5300)/(3)*x`

`x=0.07925m`............Answer