Answer: The required product is
![8y^3+6y^2-29y+15.](https://img.qammunity.org/2019/formulas/mathematics/high-school/n9l1d53yn8tlilq1ad6ftx69vnd3gp0eh0.png)
Step-by-step explanation: We are given to find the following product :
![P=(4y-3)(2y^2+3y-5).](https://img.qammunity.org/2019/formulas/mathematics/high-school/ueiknhotyi4e1gc8tjo84n4z8lpisqo68u.png)
To find the given product, we need to multiply each term of the first expression to each term of the second expression.
The multiplication is as follows :
![P\\\\=(4y-3)(2y^2+3y-5)\\\\=4y(2y^2+3y-5)-3(2y^2+3y-5)\\\\=8y^3+12y^2-20y-6y^2-9y+15\\\\=8y^3+6y^2-29y+15.](https://img.qammunity.org/2019/formulas/mathematics/high-school/qbrd5sggmj64p2jt57v7lowlzwtmpdq6xa.png)
Thus, the required product is
![8y^3+6y^2-29y+15.](https://img.qammunity.org/2019/formulas/mathematics/high-school/n9l1d53yn8tlilq1ad6ftx69vnd3gp0eh0.png)