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A pair of dice is rolled. find the probability of rolling a sum between 3 and 8

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It does not say is btw 3 and 8 inclusive so we can assume is sum 4,5,6, and 7

Sum 4 is made 1+3, 2+2
Sum 5 is made 1+4, 2+3
Sum 6 is made 1+5, 2+4, 3+3
Sum 7 is made 1+6, 2+5, 3+4
So there are 10 ways to make the sum 4,5,6,7

The total number of possible sums 10+11=21
Sum of 2 is 1+1
Sum of 3 is 1+2
Sum of 8 is 2+6, 3+5, 4+4
Sum of 9 is 3+6, 4+5
Sum of 10 is 4+6, 5+5
Sum of 11 is 5+6
Sum of 12 is 6+6

Probably = 10/21
User Sathish Manohar
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