Question

A sled travels 15 meters down a slope inclined at 30 degrees with a horizontal. What is the horizontal displacement of the sled?

Answer 1

Length of the slope is given as

`L = 15 m`

also the inclination is given as

`\theta = 30 degree`

now the horizontal displacement is let say "x"

now from geometry we can say

`(x)/(L) = cos30`

`x = L cos30`

now substitute all values in it

`x = 15 * cos30`

`x = 12.99 m`

so it will displace horizontally by 12.99 m