solution-
If we have to choose an odd number less than 5, then that number must be either 1or 3.
therefore, the probability of choosing these two numbers out of 9 numbers (that is from 1 to 9)=(2/9).
There is a 50% (that is 0.5) chance that the first number is 1 .
If it is 1, and their sum is less than 5, then the second number is 1, 2, or 3 .
The probability that it is chosen from 9 numbers=(3/9)
There is also a 50% (that is 0.5) chance that the first number is 3 .
If it is 3, and their sum is less than 5, then the second number will be 1 .
Therefore, the probability that it is chosen from 9 numbers=(1/9)
Therefore, the probability that the sum of the two numbers is less than 5 is-
=(2/9)×[ (0.5 x 3/9) + (0.5 x 1/9) ] = (2/9)×[1.5/9+0.5/9]
=(2/9)×(2/9)
=4/81 =0.0494 =4.94% (approx.)