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What is the equation of the line that is perpendicular y=1/5x+4 and that passes through (5,–4)?

User MrKekson
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2 Answers

2 votes

Answer:

The answer is B. y= -5x + 21

Explanation:

It is right on EDG2020! Have a nice day.

User HenriqueMS
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4.7k points
5 votes

The equation of the line that passes through (5, -4)

and is perpendicular to line y = 1/5x + 4

is y= -5x + 21

The slope that is perpendicular to the slope 1/5x is -5x.

To find a perpendicular slope, you take the negative reciprocal.

The negative reciprocal of 1/5x is -5/1x, or -5x

However, y = -5x + 4 does NOT pass through (5, -4)

Looking at the line on a graph, we can find that if the y-intercept is 21, it DOES pass through (5, -4)


User RufusVS
by
5.8k points
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