Question

a certain car travels 20 km east then turns south for 13 km finally the car turns east again for 6 km

Answer 1

a^2+b^2=c^2

20km^2+13km^2=c^2

400km^2+169km^2=c^2

23.853720...km

Answer 2

Total distance

`L = 39 km`

total displacement

`d = 29.1 km`

Step-by-step explanation:

Total distance moved by the car is total path length of the car

`L = L_1 + L_2 + L_3`

`L = 20 + 13 + 6`

`L = 39 km`

now similarly we will have

total displacement of the car towards East

`x = 20 + 6 = 26 km`

total displacement of the car towards South

`y = 13 km`

now net displacement of the car is given as

`d = √(13^2 + 26^2)`

`d = 29.1 km`