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CAN SOMEONE PLEASE HELP?

What is the value of t? t−12/2=3t/2−3 a. –3 b. –1 c. 1 3




The t-12 is over the 2 and the 3t is over the 2. They are fractions.

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(t - 12)/(2) = (3t)/(2) - 3 \\ (t - 12)/(2) = (3t)/(2) - (3 * 2)/(1 * 2) \\ (t - 12)/(2) = (3t)/(2) - (6)/(2) \\ (t - 12)/(2) = (3t - 6)/(2) \\ t - 12 = 3t - 6 \\ 3t - t = - 12 + 6 \\ 2t = - 6 \\ t = ( - 6)/(2) \\ t = - 3
The answer is t = -3
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