Question

Elinor determined that a triangle with side lengths 6, 10, and 8 does not form a right triangle.62 + 102 = 8236 + 100 = 64136 ≠ 64Is her answer correct?No, she should have added 82 and 102 and compared that to 62.No, she should have subtracted 102 from 82 and compared that to 62.No, she should have added 62 and 82 and compared that to 102.Yes, she is correct.

Answer 1

It is C

No, she should have added 6^2 and 8^2 and compared that to 10^2.

Explanation:

I just answered that questions

Answer 2

Option 3rd is correct

No,

she should have added
`6^2` and
`8^2` and compared that to
`10^2`

Explanation:

In a right angle triangle, we use Pythagorean theorem.

Pythagorean theorem states that

the sum of the squares of two sides must equal the square of the third side(the side facing the right angle).

i.e,
`\text{Hypotenuse side}^2=\text{sum of the square of two side}`

Given a triangle with side lengths 6, 10, and 8.

If we square all the given sides, we get;

`6^2 = 36`,

`8^2 = 64`

`10^2=100`

It can be seen that the sum of 36 and 64 is 100

⇒
`6^2+8^2 = 10^2`

which satisfies the Pythagorean theorem.

⇒ The triangle is right-angled with the side lengths 6 units and 8 units forming the right angle and the side length 10 units being the hypotenuse.

Therefore, her answer is incorrect, she should have added
`6^2` and
`8^2` and compared that to
`10^2`