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How do you find a vector of length 10 in the direction of v equals=left angle 3 comma negative 2 right angle 3,−2?

1 Answer

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Your vector will be 10 times the unit vector in that direction. The unit vector is found by dividing the given vector by its length.

|| <3, -2> || = √(3² +(-2)²) = √13

Your vector of length 10 is then

... V = (10/√13)<3, -2> = <(30/13)√13, (-20/13)√13> ≈ <8.32, -5.55>

User Tom Manterfield
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