Question

If 18.43 ml of a 0.1274 m naoh solution is needed to reach the first equivalence point in titration of a 0.2700g sample of amino aci, what is the molecular weight of the acid

Answer 1

Moles of NaOH required to reach the first equivalence point

=
`18.43mL*(1L)/(1000mL) *(0.1274molNaOH)/(1L)  =0.00235molNaOH`

0.00235 mol NaOH is required to reach the first equivalence point when NaOH is titrated with an amino acid.

So the moles of NaOH = Moles of amino acid in the solution

Moles of amino acid = 0.00235 mol amino acid

The given mass of amino acid =0.2700g

Calculating the molar mass of amino acid from mass and number of moles:

`(0.2700g)/(0.00235mol) =114.9g/mol`