Question

PLEASE HELP I NEED HELP ASAP

What is the equation of a line perpendicular to y=x+12 that passes through (12,3) ?

I KNOW THE STEPS BUT I NEED TO KNOW IF M = 1 in y=mx+b

Answer 1

`y=-x+15`

Explanation:

Slope-intercept form is written as
`y=mx+b` where
`m` is the slope and
`b` is the y-intercept.

Any line perpendicular to a given line with slope
`m` has a slope of
`-(1)/(m)`. Therefore, the slope of a line perpendicular to
`y=x+12` is
`-(1)/(1)=-1`.

We can now plug the coordinate it passes through into our slope-intercept form equation to solve for the y-intercept:

`3=-1(12)+b,\\b=15`

Therefore, the equation of the line that is perpendicular to
`y=x+12` and passes through the coordinates
`(12,3)` is
`\fbox{$y=-x+15$}`.