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The lengths of the sides of a triangle are consecutive even integers. find the length of the longest side if it is 22 units shorter than the perimeter

User Prgrm
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2 Answers

6 votes

Final answer:

The sides of the triangle are 10 units, 12 units, and 14 units, with the longest side being 14 units. We establish a system of equations based on the properties given and solve for the lengths of the consecutive even integer sides.

Step-by-step explanation:

To solve the problem of finding the lengths of the sides of a triangle where the sides are consecutive even integers and the longest side is 22 units shorter than the perimeter, we can establish a system of equations. Let's denote the shortest side as 'x', the middle side as 'x+2', and the longest side as 'x+4'. The perimeter of the triangle is the sum of its sides, so we have:

P = x + (x + 2) + (x + 4)

According to the problem, the longest side (x + 4) is 22 units shorter than the perimeter:

x + 4 = P - 22

Substituting the expression for the perimeter we get:

x + 4 = (x + x + 2 + x + 4) - 22

Simplifying this equation we find:

x + 4 = 3x + 6 - 22

x + 4 = 3x - 16

2x = 20

x = 10

Therefore, the sides of the triangle are 10 units, 12 units, and 14 units, with the longest side being 14 units.

User Stackonfire
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perimeter-longest side=(10+12+14) - 14=22

User Ben Hayward
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