Question

Hi can you help me please?❤

Answer 1

• Perimeter: Sum of all side lengths.

1.

So firstly, we are given the perimeter, which is 35 ft. To find the value of s, add all the side lengths up, equal it to 35, and solve for s:

`s+s-3+s+5=35\\3s+2=35\\3s=33\\s=11`

So now we know that the first side is 11 ft. To find the other two sides, plug the value of s into their expressions and solve:

`\large \textsf{Second Side}\\\\11-3=8\\\\\large \textsf{Third Side}\\\\11+5=16`

(The process is the same for the next two problems, so I'll go through them real quickly.)

2.

Given: Perimeter is 72 ft.

`s+2s+3s=72\\6s=72\\s=12`

The first side is 12 ft.

`\large \textsf{Second Side}\\\\3*12=36\\\\\large \textsf{Third Side}\\\\2*12=24`

3.

Given: Perimeter is 47 ft.

`4s+s+s-7=47\\6s-7=47\\6s=54\\s=9`

The first side is 9 ft.

`\large \textsf{Second Side}\\\\9-7=2\\\\\large \textsf{Third Side}\\\\4*9=36`

Answer 2

The problems are all the same sort: add the side lengths to find the perimeter, make use of the information you have about the perimeter to solve the resulting equation, go back and use that solution to find the side lengths.

1. s + (s+5) + (s-3) = 35

... 3s +2 = 35

... s = (35 -2)/3 = 11

Side lengths are s=11, s+5=16, s-3=8. Perimeter is given as 35, but we can check to make sure: 11 + 16 + 8 = 35.

2. s +3s +2s = 72

... 6s = 72

... s = 72/6 = 12

Side lengths are: s=12, 3s=36, 2s=24. Perimeter is given as 72, but we can check: 12 +36 +24 = 72.

3. s +(s-7) +4s = 47

... 6s -7 = 47

... s = (47 +7)/6 = 9

Side lengths are: s=9, s-7=2, 4s=36. Perimeter is given as 47, but can be verified as 9 +2 +36 = 47.

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Please be aware that the "triangles" in problems 2 and 3 are not real triangles. The "triangle" of problem 2 will look like a straight line of length 36. Its area will be zero.

The "triangle" of problem 3 cannot be drawn, as the ends of the legs cannot be made to meet. The sum of the shortest two legs (9+2=11) should be longer than the longest leg, but is not. (11 is not greater than 36)

That is, problems 2 and 3 are problems in math only; not problems in geometry.