we know that
Any function f(x) is continuous at x=a only if
![\lim_(x \to a-) f(x) = \lim_(x \to a+) f(x)=f(a)](https://img.qammunity.org/2019/formulas/mathematics/high-school/cbs70s9d3ebkdi5h6les7srq0ubl45odo2.png)
We can see that this curve is smooth everywhere except at x=3
so, we will check continuity at x=3
Left limit is:
![\lim_(x \to 3-) f(x) = -\infty](https://img.qammunity.org/2019/formulas/mathematics/high-school/6xa6cjqpb1lh0f81ehcphndmezrtl0cc98.png)
Right limit is:
![\lim_(x \to 3+) f(x) = +\infty](https://img.qammunity.org/2019/formulas/mathematics/high-school/ezr7drlhmteaevgwomtely2h182uxge1vs.png)
Functional value:
![f(3)= DNE](https://img.qammunity.org/2019/formulas/mathematics/high-school/q7xokskh3egbbz6sq8emb5xptvnq175v96.png)
we can see that left limit is not equal to right limit
so, limit does not not exist
so, this function is discontinuous at x=3
Since, limit does not exist
so, there will be non-removal discontinuity at x=3
so, option-C........Answer