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Please help me with this!

Choose the right system for each equation(picture)
Picture one: Inconsistent, consistent, or equivalent?
Picture two: Inconsistent, consistent, or equivalent?
picture three: Inconsistent, consistent, or equivalent?
picture four: Inconsistent, consistent, or equivalent?
picture five: Inconsistent, consistent, or equivalent?

Please help me with this! Choose the right system for each equation(picture) Picture-example-1
Please help me with this! Choose the right system for each equation(picture) Picture-example-1
Please help me with this! Choose the right system for each equation(picture) Picture-example-2
Please help me with this! Choose the right system for each equation(picture) Picture-example-3
Please help me with this! Choose the right system for each equation(picture) Picture-example-4
Please help me with this! Choose the right system for each equation(picture) Picture-example-5

2 Answers

3 votes

pic 1: equivalent

pic 2 : consistent

pic 3: consistent

pic 4: inconsistent

pic 5: equivalent.

number 6 incase you have it y=3x-2, 3x-y=4 :inconsistent

Explanation:

consistent means they share a point, equivalent is when they have infinite or many touching points so basically the same line. And inconsistent means no sharing points so two different lines.

User Ashey
by
6.4k points
4 votes

1. The first equation is - 2x + 5y = 0

Second equation is
y = (2)/(5) x

5y = 2x

- 2x + 5y = 0

Hence, the two equations are equivalent.

2.
a_(1) = 2, a_(2) = - 2


b_(1) = -1,  b_(2) = -1


(a_(1) )/(a_(2)) =(2)/(-2) = -1


(b_(1) )/(b_(2)) = (-1)/(-1)  = 1


(a_(1) )/(a_(2)) \\eq (b_(1) )/(b_(2))

Hence, the equations are consistent.

3.
a_(1) = 4, a_(2) = 6


b_(1) = -1, b_(2) = -1


(a_(1) )/(a_(2)) =(4)/(6) = (2 )/(3)


(b_(1) )/(b_(2)) = (-1)/(-1) = 1


(a_(1) )/(a_(2)) \\eq (b_(1) )/(b_(2))

Hence, the equations are consistent.

4. Equations can be re-arranged as:

x + y - 4 = 0 and

x + y + 6 = 0


a_(1) = 1, a_(2) = 1


b_(1) = 1, b_(2) = 1


c_(1) = -4, c_(2) = 6


(a_(1) )/(a_(2)) =(1)/(1) = 1


(b_(1) )/(b_(2)) =(1)/(1) = 1


(c_(1) )/(c_(2)) =(-4)/(6) = (-2)/(3)


(a_(1) )/(a_(2)) = (b_(1) )/(b_(2)) \\eq (c_(1) )/(c_(2))

Hence, the equations are inconsistent.

5. If we multiply the first equation by 4, we will get,

2y = -4x + 20 which is the second equation.

Hence, the equations are equivalent.

User Greg Wilson
by
6.3k points
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