interesting
just solve them to find x and y
3x+4y=52
5x+y=30
eliminate
eliminate y
multiply 2nd equation by -4
-20x-4y=-120
add to other equation
3x+4y=52
-20x-4y=-120 +
-17x+0y=-68
-17x=-68
divide both sides by -17
x=4
subsitute back
3x+4y=52
3(4)+4y=52
12+4y=52
minus 12 both sides
4y=40
divide both sides by 4
y=10
x=4 and y=10
subsitute
8x-2y=8(4)-2(10)=32-20=12
answer is 12
C is answer