Question

Given that sintheta = 6/17, find sectheta

PLEASE HELP ME AND SHOW WORK PLEASE ILL BE SO HAPPY AND ILL MEDAL

Answer 1

The answer is
`(17)/(√(253))` which is the fraction of 17 over sqrt(253). The notation "sqrt" is shorthand for "square root"

Check out the attached image to see the steps on how I got that answer.

Edit: if you need the steps for the pythagorean theorem, then....

a^2+b^2 = c^2

6^2+b^2 = 17^2

36+b^2 = 289

b^2 = 289-36

b^2 = 253

b = sqrt(253)

So that's how I got the square root of 253 as the adjacent side