Question

`((3x^-3y^4)/(5x^6y^7 ))^-2`

Answer 1

9514 1404 393

Answer:

(25/9)x^18·y^6

Explanation:

Maybe you want this simplified.

The appropriate rules of exponents are ...

(a^b)/(a^c) = a^(b-c)

(a^b)^c = a^(bc)

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`\left((3x^(-3)y^4)/(5x^6y^7)\right)^(-2)=\left((3x^(-3-6)y^(4-7))/(5)\right)^(-2)=(3^(-2))/(5^(-2))\cdot x^((-2)(-9))y^((-2)(-3))\\\\=\boxed{(25)/(9)x^(18)y^(6)}`