Question

The sum of four consecutive odd integers is –72. Write an equation to model this situation, and find the values of the four integers.

A.
n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –23; n + 4 = –25; n + 6 = –27

B.
n + (n – 2) + (n – 4) + (n – 6) = –72; n = – 21; n – 2 = –23; n – 4 = –25; n – 6 = – 27

C.
n – (n + 2) – (n + 4) – (n + 6) = –72; n = –20; n + 2 = –18; n + 4 = –16; n + 6 = –14

D.
n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –19; n + 4 = –17; n + 6 = –15

Answer 1

D. n+n+2+n+4+6= -72; n= -21; n+2= -19; n+4= -17; n+6= -15

There are 2 below and 2 above it.

-15, -17, -19, -21

Explanation:

the sum of four consecutive odd integers is -72. write an equation to model this situation, and find the values of the four integers .

n + n+2 + n+4 + n+6 = -72

4n + 12 = -72

or

-72/4 = -18, the center