Question

(4y+8)^2=64

`(4y + 8) ^(2) = 64`

Answer 1

y = 0 or y = -4

Explanation:

Solve for y over the real numbers:

(4 y + 8)^2 = 64

Take the square root of both sides:

4 y + 8 = 8 or 4 y + 8 = -8

Subtract 8 from both sides:

4 y = 0 or 4 y + 8 = -8

Divide both sides by 4:

y = 0 or 4 y + 8 = -8

Subtract 8 from both sides:

y = 0 or 4 y = -16

Divide both sides by 4:

Answer: y = 0 or y = -4