Question

The energy required to ionize magnesium is 738 kj/mol. What minimum frequency of light is required to ionize magnesium

Answer 1

The minimum frequency required to ionize the photon is 111.31 ×
`10^(37)` Hertz

Given:

Energy = 378
`(kJ)/(mol)`

To find:

Minimum frequency of light required to ionize magnesium = ?

Formula used:

The energy of photon of light is given by,

E = h v

Where E = Energy of magnesium

h = planks constant

v = minimum frequency of photon

Solution:

The energy of photon of light is given by,

E = h v

Where E = Energy of magnesium

h = planks constant

v = minimum frequency of photon

738 ×
`10^(3)` = 6.63 ×
`10^(-34)` × v

v = 111.31 ×
`10^(37)` Hertz

The minimum frequency required to ionize the photon is 111.31 ×
`10^(37)` Hertz

Answer 2

Step-by-step explanation:

Relation between energy and frequency is as follows.

E =
`h \\u`

where, E = energy

h = planck's constant =
`6.626 * 10^(-34)` Js

`\\u` = frequency

As it is given that value of energy is 738 kJ/mol.

E =
`(738 * 1000 J)/(6.022 * 10^(23))`

=
`1.22 * 10^(-18)` J

Hence, putting the given values into the above formula as follows.

E =
`h \\u`

`1.22 * 10^(-18)` J =
`6.626 * 10^(-34) Js * \\u`

`\\u` =
`1.84 * 10^(15)` per second

Thus, we can conclude that
`1.84 * 10^(15)` per second is the minimum frequency of light which is required to ionize magnesium.