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How many nanoseconds does it take light to travel a distance of 3.20 km in vacuum?

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Distance covered by the light = 3.20 km = 3200 meter

speed of the light is
c = 3* 10^8 m/s

so here time to cover the given distance


t = (d)/(c)


t = (3200)/(3*10^8)


t = 1.067 * 10^(-5)s

as we know that


1 ns = 10^(-9) s

So the time tocover the distance in nanosecond unit is


t = 10670 ns

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