Question

The mass of a single palladium atom is 1.77×10-22 grams. How many palladium atoms would there be in 201 milligrams of palladium?

Answer 1

Answer: The number of palladium atoms is
`113.6* 10^(19)`

Step-by-step explanation:

We are given:

Mass of single palladium atom =
`1.77* 10^(-22)g`

Total mass of palladium = 201 mg =
`201* 10^(-3)g` (Conversion factor: 1 g = 1000 mg)

To calculate the number of palladium atoms, we divide the total mass of palladium to the mass of one palladium atom.

`n=\frac{\text{Total mass of palladium}}{\text{Mass of one palladium atom}}`

Putting values in above equation, we get:

`n=(201* 10^(-3)g)/(1.77* 10^(-22)g)\\\\n=113.6* 10^(19)`

Hence, the number of palladium atoms is
`113.6* 10^(19)`

Answer 2

The mass of single palladium atom is
`1.77* 10^(-22)g`. Thus, in 1 gram of palladium, the number of atoms will be:

`N=(1)/(1.77* 10^(-22))=5.65* 10^(21) atoms`

Now,

`1 g\rightarrow 5.65* 10^(21) atoms`

Also,

`201 mg=201* 10^(-3)g`

Thus,

`201* 10^(-3)g\rightarrow 201* 10^(-3)* 5.65* 10^(21) atoms=1.35* 10^(21) atoms`

Therefore, number of atoms in 201 milligrams of palladium will be
`1.35* 10^(21) atoms`.