Question

An infinite plane of charge has surface charge density 4.7 mu or micro cc/m2. How far apart are the equipotential surfaces whose potentials differ by 100 v?

Answer 1

charge density of infinite sheet is given as

`\sigma = 4.7 \mu C/m^2`

now the electric field due to this charged sheet will be constant and it is given as

`E = (\sigma)/(2\epsilon_0)`

`E = (4.7 * 10^(-6))/(2 * 8.85 * 10^(-12))`

`E = 2.66 * 10^5 N/c`

now the relation between electric field intensity and potential difference is given as

`\Delta V = E.d`

`\Delta V = 100 Volts`

`E = 2.66 * 10^5 N/C`

now we have

`d = \farc{\Delta V}{E}`

`d = (100)/(2.66* 10^5)`

`d = 3.76 * 10^(-4)m`

so it is at distance 0.376 mm from the plate