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A kangaroo jumps straight upward with a velocity of 5.77 m/s. Determine the height (to two decimal places) to which the kangaroo jumps.

User PepitoSh
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1 Answer

4 votes

Initial velocity of kangaroo in upward direction (u) = 5.77
\((m)/(s)\)

Final velocity at the highest point of the journey (v) = 0
\((m)/(s)\)

Let the maximum height reached be H.

Acceleration due to gravity = -9.8
(m)/(s^2)\)

Now, using the third equation of motion:


\(v^2 = u^2 + 2aH\)


\(0^2 = 5.77^2 - 2 * 9.8 * H\)


\(5.77^2 = 2 * 9.8 * H\)


\(H = \((5.77^2)/(19.6) \)

H = 1.698 m

The maximum height reached by kangaroo is 1.7 m.

User LDomagala
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