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Sarah throw a ball straight up in the air with initial velocity of 19.62m/s. how long will the ball be in the air

User Tuxer
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1 Answer

4 votes

Here Sarah projected the ball upwards by speed


v_i = 19.62 m/s

here the acceleration is due to gravity


a = 9.81 m/s^2

now when ball again lends on the ground the displacement of ball will be zero


\delta y = v_y * t + (1)/(2) at^2


0 = 19.62 t - (1)/(2)9.81*t^2

by solving above equation


t = 4 s

so it will take 4 s to reach back on ground

User Hamid Mosalla
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