Question

(b) let's say a slingshot is used to shoot a marble straight up from the ground (s0 = 0) with an initial velocity of 11 meters per second. What is the marbles maximum height above the ground

Answer 1

Answer: 6.17 m

When a slingshot shoots a marble with initial velocity,
`u=11 m/s`, it reaches a certain height
`(s)` and starts dropping from their under gravity
`g=9.8m/s^2`. At the maximum height, instantaneous velocity,
`v=0 m/s`

We would use the following equation of motion to find the maximum height reached:

`2as=v^2-u^2`

where,
`a`is the acceleration ,
`s` is the distance,
`v` is the final velocity,
`u` is the initial velocity.

`\Rightarrow s=(v^2-u^2)/(2a)=(0-(11m/s)^2)/(2*-9.8m/s^2)=(-121)/(-19.6)m=6.17 m`

Marble reaches a maximum height of 6.17 m above the ground.