A sheet of gold foil has a volume of 0.750 cm3. If the foil measures 50.0cm by 10.0cm, what is the thickness of the foil?

Question

asked Feb 9, 2019 161k views

1 Answer

Andrey Chausenko · Answer 1 · 2019-02-15T08:18:56+0000

To calculate the thickness of foil, we use formula of volume as

V= l w t

Here, l is the length of the foil, w is the width of the foil and t is the thickness of the foil.

Given,
$V = 0.750 \ cm^3$ ,
l = 50 cm and
$w = 10 \ cm$ .

Substituting theses values in above equation, we get

$0.750 \ cm^3 = 50 cm * 10 \ cm * t \\\\ t =  0.0015 cm$

Thus, the thickness of the foil is 0.0015 cm.