Question

Mt. Everest is more than 8 000 m high. How fast would an object be moving if it could free fall to sea level after being released from an 8000-m elevation? (ignore air resistance.)

Answer 1

By kinematics equation we will say

displacement of object = 8000 m

acceleration = 9.8 ms^2

initial speed = 0

`v_f^2 - v_i^2 = 2 a d`

`v_f^2 - 0 = 2*9.8 * 8000`

`v_f^2 = 156800`

`v_f = 395.98 m/s`

so it will move with speed 395.98 m/s