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Consider the quadratic equation below. 4x^2-5=3x+4 Determine the correct set-up for solving the equation using the quadratic formula.

2 Answers

4 votes


4x^2-5=3x+4


4x^2 - 3x - 5 - 4 = 0


4x^2 - 3x -9 = 0


x= (3 \pm √(3^2 - 4(4)(-9)))/(2(4))


x = \frac 1 8 (3 \pm √(9(1 + 16)))


x = \frac 1 8 (3 \pm 3√(17))


User Ohjeah
by
8.7k points
5 votes

Answer:

Solutions are 1.92 and -1.17

Explanation:

The general solutions of quadratic equation of the form ax²+bx+c = 0 is given by
(-b+√(b^2-4ac) )/(2a) and
(-b-√(b^2-4ac) )/(2a)

Here the the equation is 4x²-5 = 3x + 4

On rearranging

4x²-3x-5-4 = 0

4x²-3x-9 = 0

Comparing with ax²+bx+c = 0, we will get a = 4, b = -3 and c = -9

The solutions are given by


(-(-3)+√((-3)^2-4*4*(-9)) )/(2*4) and
(-(-3)-√((-3)^2-4*4*(-9)) )/(2*4)


(3+√(153) )/(8) and
(3-√(153) )/(8)

1.92 and -1.17

User Daserge
by
8.3k points

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